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Chapter 5 of 10

§G-orbifolds

We construct VOAs by taking fixed points of automorphism groups, using the subalgebra and ideal properties from the preceding chapter.

§5.1 The fixed-point VOA

Definition 5.1 (Fixed-point subalgebra and orbifold)

Let G≤Aut⁡(V)G\leq\operatorname{Aut}(V). The fixed-point subalgebra is

VG={a∈V:ga=a for every g∈G},YVG(a,x)=YV(a,x)∣VG.V^G=\{a\in V:ga=a\text{ for every }g\in G\}, \qquad Y_{V^G}(a,x)=Y_V(a,x)|_{V^G}.

When GG is finite, we call VGV^G the GG-orbifold of VV.

Proposition 5.2 (Inherited conformal structure)

For any G≤Aut⁡(V)G\leq\operatorname{Aut}(V), VGV^G is a full VOA subalgebra of VV, with

1VG=1V,ωVG=ωV,(VG)h=(Vh)G,cVG=cV.\mathbf1_{V^G}=\mathbf1_V,\qquad \omega_{V^G}=\omega_V,\qquad (V^G)_h=(V_h)^G,\qquad c_{V^G}=c_V.

CFT type is inherited. In particular, VV is an extension of VGV^G, proper whenever G≠{1}G\ne\{1\}.

Exercise. Prove Proposition 5.2 using Proposition 4.2 and the identity

g(Y(a,x)b)=Y(ga,x)gb=Y(a,x)b(a,b∈VG).g\bigl(Y(a,x)b\bigr)=Y(ga,x)gb=Y(a,x)b \quad(a,b\in V^G).

Thus taking fixed points restricts the states while retaining the conformal field; it does not divide the central charge by ∣G∣|G|.

§5.2 Averaging

For the rest of this chapter, assume GG is finite.

Proposition 5.3 (Averaging projection)

The averaging operator

RG=1∣G∣∑g∈GgR_G=\frac1{|G|}\sum_{g\in G}g

preserves weights and satisfies

RG2=RG,im⁡RG=VG,V=VG⊕ker⁡RG.R_G^2=R_G,\qquad \operatorname{im}R_G=V^G, \qquad V=V^G\oplus\ker R_G.

For u∈VGu\in V^G and v∈Vv\in V,

RG(Y(u,x)v)=Y(u,x)RGv,RG(Y(v,x)u)=Y(RGv,x)u.R_G\bigl(Y(u,x)v\bigr)=Y(u,x)R_Gv, \qquad R_G\bigl(Y(v,x)u\bigr)=Y(R_Gv,x)u.

Consequently, both summands are preserved by the fields of VGV^G.

Exercise. Prove Proposition 5.3 by averaging the automorphism identity. The projection RGR_G is generally not a VOA homomorphism: the identities above require one state to be invariant.

§5.3 Simplicity

Theorem 5.4 (Simplicity of finite orbifolds)

If VV is simple and G≤Aut⁡(V)G\leq\operatorname{Aut}(V) is finite, then VGV^G is simple.

Proof.

We use the cyclicity result that, for any nonzero uu in a simple VOA VV, the coefficients of Y(a,x)uY(a,x)u, as aa ranges over VV, span VV; see Dong–Li–Mason, Proposition 2.1.

Let 0≠I⊆VG0\ne I\subseteq V^G be an ideal and choose 0≠u∈I0\ne u\in I. By cyclicity, there are finitely many ai∈Va_i\in V and Laurent polynomials fi(x)f_i(x) such that

1=∑iRes⁡xfi(x)Y(ai,x)u.\mathbf1=\sum_i\operatorname{Res}_x f_i(x)Y(a_i,x)u.

Apply RGR_G and use Proposition 5.3:

1=∑iRes⁡xfi(x)Y(RGai,x)u∈I.\mathbf1=\sum_i\operatorname{Res}_x f_i(x)Y(R_Ga_i,x)u\in I.

Since RGai∈VGR_Ga_i\in V^G, each residue lies in II. Creation now gives a=Y(a,x)1∣x=0∈Ia=\left.Y(a,x)\mathbf1\right|_{x=0}\in I for every a∈VGa\in V^G. Thus I=VGI=V^G.

§5.4 Fixed points in stages

Proposition 5.5 (Subgroups and successive orbifolds)

If H≤GH\leq G, then

VG⊆VH⊆VV^G\subseteq V^H\subseteq V

are full VOA inclusions. If H⊴GH\trianglelefteq G, the quotient G/HG/H acts on VHV^H by VOA automorphisms through (gH)a=ga(gH)a=ga, and

(VH)G/H=VG.(V^H)^{G/H}=V^G.

Exercise. Check that normality makes the quotient action well-defined and that being fixed by G/HG/H inside VHV^H is equivalent to being fixed by GG. The quotient action need not be faithful for a general VV; the displayed equality uses its fixed vectors.

The construction above requires no rationality assumption. Questions about modules, rationality, and extensions involving twisted sectors will be treated after module theory is introduced.

§5.5 References

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